CBSE Class 9 Science Sample Paper

Sample Paper Class 9

We have provided CBSE Class 9 Science Sample Paper with solutions below. These Sample guess papers have been prepared as per the latest examination guidelines and paper pattern issued by CBSE. Students of Class 9 should practice all practice papers for Class 9 Science given below as it will help them top improve their understanding of the subject. Please click on the links below to access free sample paper for Science Class 9.

Sample Papers for Class 9 Science

CBSE Class 10 Science Term 2 Sample Paper

CBSE Class 10 Science Term 2 Sample Paper

Question: Define the atomicity of a molecule of an element?
Answer: The number of atoms present in one molecule of an element is called its atomicity.

Question: Name the microorganisms which can cause acne and cholera.
OR
Give one local and one general effect of inflammation process.
Answer: Acne – Staphylococci and cholera – Vibrio cholerae
OR
Local effect : Swelling or pain
General effect: Fever or headache

Question: Which of the following has the smallest mass?
(a) 4 g of He
(b) 6.022 × 1023 atoms of He
(c) 1 atom of He
(d) 1 mole atoms of He   

Answer: C

Question: Fill in the blanks and select the correct option.
(i) is the protozoan organism that causes kala-azar. These are (ii) shaped and each has one long whip like structure. This disease is usually spread by the bite of certain types of (iii) .
      (i)                                    (ii)                                         (iii)
(a) SARS                                Saucer                                  Mosquito
(b) Leishmania                         Oval                                      Sandfly
(c) Trypanosoma                      Rod                                         Mite
(d) Ascaris                              Oval                                       Ant 

Answer: B

Question: Which of the following statements is correct?
(a) Common cold is not contagious.
(b) The common cold virus does not have its own RNA.
(c) Common cold usually takes two months to clear up.
(d) The common cold virus can leave the body through the mucus of infected people.
For question numbers 6 and 7, two statements are given- one labelled Assertion (A) and the other
labelled Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below :
(a) Both A and R are true, and R is correct explanation of the assertion.
(b) Both A and R are true, but R is not the correct explanation of the assertion.
(c) A is true, but R is false.
(d) A is false, but R is true.   

Answer: D

Question: Assertion : When 10 g of CaCO3 is decomposed, 5.6 g of residue is left and 4.4 g of CO2 escapes.
Reason : Law of conservation of mass is followed.   

Answer: A

Question: Assertion : Poliomyelitis is a highly infectious viral disease of infants and children.
Reason : Pathogen of Poliomyelitis is a very small RNA containing virus.

Answer: B
OR
Assertion : Filarial worm is transmitted to humans by Culex mosquito.
Reason : Culex prefers to breed in fresh water.
Answer Q. No. 8 and 9 contain five sub-parts each. You are expected to answer any four sub-parts in these questions.    

Answer: C

 Read the following and answer any four questions from 8(i) to 8(v).
A child pulls a toy car with a string attached to it, the car moves horizontally on the ground, but the force applied by the child is along the string held in his hand making some angle with the ground. In figure, the toy car moves along the horizontal ground surface but the force is being applied along the string, the direction of force making an angle q with the direction of motion. 

The whole of force is not being used in pulling the toy car, only its horizontal component along the ground is the effective force pulling the toy car. The work done in pulling the body will be equal to the product of horizontal component of the force and distance moved by the body, i.e.,
W = F cos θ × s

Question: A child pulls a toy car through a distance of 10 m on a smooth, horizontal floor. The string hold in child’s hand makes an angle of 60° with the horizontal surface. If the force applied by the child be 5 N, the work done by the child in pulling the toy car is
(a) 2.5 J
(b) 20 J
(c) 25 J
(d) 22 J   

Answer: C

Question: The work done on an object does not depend on the
(a) displacement
(b) angle between force and displacement
(c) force applied
(d) initial velocity of the object.   

Answer: D

Question: In case of negative work, the angle between the force and displacement is
(a) 0°
(b) 45°
(c) 90°
(d) 180° 

Answer: D

Question: Each of the following statement describes a force acting. Which force is causing work to be done?
(a) The weight of a book at rest on a table.
(b) The pull of a moving railway engine on its coaches.
(c) The tension in an elastic band wrapped around a parcel.
(d) The push of a person’s feet when standing on the floor.   

Answer: B

Question: The work done is zero if
(a) the body shows displacement in the opposite direction of the force applied
(b) the body shows displacement in the same direction as that of the force applied
(c) the body shows a displacement in perpendicular direction to the force applied
(d) the body masses obliquely to the direction of the force applied. 

Answer: B

Question: Refer to the given figures and answer any four questions from 9(i) to 9(v).
Any physical or functional change from the normal state that causes discomfort of disability, or impairs the health of a living organism is called a disease. Some of the disease causing microorganisms are viruses, bacteria,fungi protozoans etc.

Question: Figure A shows an organism called
(a) Trypanosoma
(b) Staphylococci
(c) Leishmania
(d) Streptococci. 

Answer: B

Question: Select the correct statements regarding the given figures.
(I) The organism shown in figure A is a type of bacteria.
(II) The organism shown in figure B causes sleeping sickness.
(III) Both the organisms A and B are agents of infectious diseases.
(IV) The organism in figure B is a type of fungi.
(a) (II) and (IV)
(b) (I) and (II)
(c) (I) and (III)
(d) (I), (III) and (IV)

Answer: C

Question: Which organism(s) shown in the given figures can cause pneumonia?
(a) A
(b) B
(c) Both (a) and (b)
(d) None of these 

Answer: B

Question: Figure B shows a bacterium known as
(a) E. Coli
(b) Salmonella
(c) Streptococci
(d) Clostridium 

Answer: C

Question: Organism shown in figure (A) does not causes
(a) Food poisoning
(b) Pus-filled abscesses on skin
(c) Inflammation of salivary glands
(d) Typhoid 

Answer: D

Question: Electronic configuration of a neutral atom ‘X’ is 2, 8, 6. What is the electronic configuration of X2–?
Answer: 10. X = 2, 8, 6
No. of electrons in neutral atom = 2 + 8 + 6 = 16
X + 2e– → X2–
No. of electrons in X2– = 16 + 2 = 18
Electronic configuration of X2– = 2, 8, 8

Question: Distinguish between mass and weight of a body.
OR
The Earth’s gravitational force causes an acceleration of 10 m/s2 in a 2 kg mass some where in space. How much
will the acceleration of a 5 kg mass be at the same place?
Answer: 

OR 
The acceleration produced in any body due to the gravitational pull of the Earth does not depend on the mass of the body. So, the acceleration produced in the 5 kg mass due to gravitational pull will also be 10 m/s2.

Question: If one mole of carbon atom weighs 12 gram, what is the mass (in gram) of 1 atom of carbon?
Answer: Molecular mass of carbon = 12 g
 ∴ 6.022 × 1023 atoms of carbon have mass =12g
 ∴ 1 atom of carbon has mass
= 12/6.022X1023=1.99X10-23 g

Question: Explain with reason whether the potential energy in the following cases increases or decreases:
(a) a spring is compressed,
(b) a spring is stretched,
(c) a body is taken away against the gravitational force.
Answer: (a) When a spring is compressed, work is done on the spring in compressing it. Therefore, potential energy increase.
(b) When a spring is stretched, work is done on the spring in stretching it. Therefore, potential energy increases.
(c) Work is done by us in taking the body away against the gravitational force. Therefore, potential energy increases.
OR

Question: How will you find the valency of nitrogen, oxygen and fluorine?
Answer:  (i) Nitrogen has 5 electrons in valence shell, hence
its valency is 8 – 5 = 3.
(ii) Oxygen has 6 electrons in valence shell, hence its
valency is 8 – 6 = 2.
(iii) Fluorine has 7 electrons in valence shell, hence its
valency is 8 – 7 = 1.

Question: Write the formula and names of compounds formed by

Answer: 
Formula                     Name of the compound
(a) NaHCO3                Sodium bicarbonate
(b) K2CO3                  Potassium carbonate
(c) CuSO4                   Copper(II) sulphate
(d) CuO                       Copper(II) oxide
(e) Na2SO4                   Sodium sulphate
(f) (NH4)2CO3             Ammonium carbonate

Question: Y is the ion of an element X. Y contains 13 protons,14 neutrons and 10 electrons.
(a) What is the nucleon number of Y?
(b) Draw a ‘dot and cross’ diagram to show how the electrons are arranged in an atom of X.
(c) Predict the formula of the compound that contains Y and the oxide ion.
OR
The valency of hydrogen is 1, magnesium is 2, aluminium is 3 and carbon is 4. Can you see any connection
between the valency of an element and the number of electrons it has in its outermost electron shell? What would you predict the valencies of helium (He), phosphorus (P), sulphur (S) and neon (Ne) to be?
Answer: Y is the ion of an element X.
Y contains p = 13, n = 14 and e = 10.
(a) The nucleon number of Y is (13 + 14 =) 27.
(b) An atom of X contains p = 13, n = 14 and e = 13.

carries + 3 charge.
So, the formula of the compound that contains Y and
the oxide ion is Y2O3.
OR
The valency of an element depends upon the number of electrons in the outermost shell (valence shell) of an atom of the element. The valency of an element is either equal to the number of valence electrons in an atom of the element or to the number of electrons required to complete an octet in its valence shell.
Valency of a metal = Number of valence electrons Valency of a non-metal = 8 – Number of valence electrons
Helium (He) : An atom of helium contains 2 electrons in its K shell. This shell is the outermost shell of helium which is completely filled with
2 electrons. Hence, valency of helium = 0.
Phosphorus (P) : The electronic configuration of the P atom is 2, 8, 5. Thus, it has 5 valence electrons and it is a non-metal. Hence, valency of P = 8 – 5 = 3.
Sulphur (S): The electronic configuration of an atom of S is 2, 8, 6.
Sulphur is a non-metal. Hence, valency of S = 8 – 6 = 2.
Neon (Ne) : The electronic configuration of neon is 2, 8.
The outermost shell of neon is completely filled. Hence, valency of neon = 0.

CBSE Class 9 Science Sample Paper