# Case Study Chapter 5 Arithmetic Progression Mathematics

Please refer to Case Study Chapter 5 Arithmetic Progression Mathematics with answers provided below. These case study based questions are expected to come in the upcoming Class 10 Mathematics examinations. We have provided case study questions class 10 maths for all chapters on our website as per the latest examination pattern issued by CBSE, NCERT, and KVS.

## Chapter 5 Arithmetic Progression Case study Questions Class 10 Maths

India is competitive manufacturing location due to the low cost of manpower and strong technical and engineering capabilities contributing to higher quality production runs. The  roduction of TV sets in a factory increases uniformly by a fixed number every year. It produced 16000 sets in 6th year and 22600 in 9th year.
Based on the above information, answer the following questions:

Question. In which year, the production is Rs 29,200.

5000 + (n – 1) 2200 = 29200 ⇒ n = 12th year

Question. Find the production during first 3 years.

Production during first 3 year = 5000 + 7200 + 9400 = 21600

Question. Find the production during 8th year.

Production during 8th year is (a + 7d) = 5000 + 2(2200) = 20400

Question. Find the difference of the production during 7th year and 4th year.

Difference = (a + 6d) – (a + 3d) = 3d = 6600

Your friend Veer wants to participate in a 200m race. He can currently run that distance in 51 seconds and with each day of practice it takes him 2 seconds less.He wants to do in 31 seconds .

Question. If nth term of an AP is given by an = 2n + 3 then common difference of an AP is
(a) 2
(b) 3
(c) 5
(d) 1

A

Question. The value of x, for which 2x, x+ 10, 3x + 2 are three consecutive terms of an AP
(a) 6
(b) –6
(c) 18
(d) –18